This question involves reasoning about one-dimensional and 2-dimensional arrays of integers. You will write three static methods, all of which are in a single enclosing class, named DiverseArray (not shown). The first method returns the sum of the values of a one-dimensional array; the second method returns an array that represents the sums of the rows of a two-dimensional array and the third method analyzes row sums.

A)

Write a static method arraySum that calculates and returns the sum of the entries in a specified one-dimensional array. The following example shows an array arr1 and the value returned by a call to arraySum.

In our games backend, we chave created an array collisions detailing the presence of collisions on the game map. Creating a sum of these collisions, and then dividing by 1025 will give us the number of collision areas at one time. To perform this, we will have to write a method arraySum, to return the sum of the entries of a one-dimensional array, arr.

public static int arraySum(int[] arr) {
    int sum = 0; 
    for (int i : arr) {
        sum += i;
    }
    return sum;
}

public class Main {
    public static void main(String[] args) {
        int[]collisions = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 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        int sum = arraySum(collisions);
        System.out.println(sum);
    }
}

Main.main(null);

189625

189625/1025 = 185. This function was useful because it now I know that there are 185 collision areas.

B)

Write a static method rowSums that calculates the sums of each of the rows in a given two-dimensional array and returns these sums in a one-dimensional array. The method has one parameter, a two-dimensional array arr2D of int values. The array is in row-major order: arr2D [ r ] [ c ] is the entry at row r and column c. The method returns a one-dimensional array with one entry for each row of arr2D such that each entry is the sum of the corresponding row in arr2D. As a reminder, each row of a two-dimensional array is a one-dimensional array.

Below I have code for a collision Map2d array prototype we used at the very begining of our game. Then I have written code for the rowSums method.

public class CollisionData {
    public static void main(String[] args) {
        int[][] collisionMap = {
            {0, 1, 0, 0, 1},
            {1, 0, 0, 1, 0},
            {0, 0, 1, 0, 0},
            {0, 1, 0, 0, 1},
            {1, 0, 0, 1, 0}
        };

        int[] rowSums = rowSums(collisionMap); // Corrected variable name
        System.out.println("Row sums: " + Arrays.toString(rowSums));
    }

    // METHOD FOR PART B HERE
    public static int[] rowSums(int[][] arr2D) {
        int[] sums = new int[arr2D.length]; // One entry for each row
        for (int i = 0; i < arr2D.length; i++) {
            sums[i] = arraySum(arr2D[i]); // Utilizing the arraySum method
        }
        return sums;
    }

    // METHOD FOR PART A HERE
    public static int arraySum(int[] arr) {
        int sum = 0;
        for (int i : arr) {
            sum += i;
        }
        return sum;
    }
}

CollisionData.main(null);

Row sums: [2, 2, 1, 2, 2]

C)

Write a static method isDiverse that determines whether or not a given two-dimensional array is diverse. The method has one parameter: a two-dimensional array arr2D of int values. The method should return true if all the row sums in the given array are unique; otherwise, it should return false. In the arrays shown above, the call isDiverse (mat1) returns true and the call isDiverse(mat2) returns false.

public static boolean isDiverse(int[][] arr2D) {
    int[] rowSums = rowSums(arr2D);
    for (int i = 0; i < rowSums.length; i++) {
        for (int k = i + 1; k < rowSums.length; k++) {
            if (rowSums[k] == rowSums[k]) {
                return false;
            }
        }
    }
    return true;
}

public class CollisionData {
    public static void main(String[] args) {
        int[][] collisionMap = {
            {0, 1, 0, 0, 1},
            {1, 0, 0, 1, 0},
            {0, 0, 1, 0, 0},
            {0, 1, 0, 0, 1},
            {1, 0, 0, 1, 0}
        };

        int[] rowSums = rowSums(collisionMap);
        System.out.println("Row sums: " + Arrays.toString(rowSums));

        System.out.println("Is diverse: " + isDiverse(collisionMap));
    }

    // METHOD FOR PART B HERE
    public static int[] rowSums(int[][] arr2D) {
        int[] sums = new int[arr2D.length]; // One entry for each row
        for (int i = 0; i < arr2D.length; i++) {
            sums[i] = arraySum(arr2D[i]); // Utilizing the arraySum method
        }
        return sums;
    }

    // METHOD FOR PART A HERE
    public static int arraySum(int[] arr) {
        int sum = 0;
        for (int i : arr) {
            sum += i;
        }
        return sum;
    }

    // METHOD FOR PART C HERE
    public static boolean isDiverse(int[][] arr2D) {
        int[] rowSums = rowSums(arr2D);
        for (int i = 0; i < rowSums.length; i++) {
            for (int j = i + 1; j < rowSums.length; j++) {
                if (rowSums[i] == rowSums[j]) {
                    return false;
                }
            }
        }
        return true;
    }
}

CollisionData.main(null);

Row sums: [2, 2, 1, 2, 2]
Is diverse: false