Homework 3.17 - 3.18
Vocabulary
- Problem: a general description of a task that can or cannot be solved algorithmically
- Decision Problem: A problem with a yes or no answer
- Organization Problem: a problem with a goal of finding the best answer Instance: a problem with a specific input
- Efficiency: amount of computing needed to solve a problem
- Polynomial Efficiency (Good): more work takes a proportional amount of time (1 job is +2 time)
- Exponential Efficiency (Bad): more work takes an exponential amount more time (1 job is 2x time)
- Heuristic Approach: When optimal solutions are inefficient, look for a possibly optimal solution that is more efficient
- Decidable Problem: A decision problem that has a clear solution that will always make a correct output
- Undecidable Problem: A decision problem with no solution that is not gaurenteed to produce the correct output
Extra Notes
- exponential efficiences take much longer than polynomial because the increase rapidly
- Heruestic Approach: situation where the list of requirements that must me met with an ideal solution. Sometimes it is easier and less time consuming to reach a less ideal solution. Finding a solution that is 'close enough' to be an acceptable output.
import time
numlist = [1,3,5,7,9,11,13,15,17,19]
valuelist = [0,3,6,9,12,15,18,21]
def isvalue(value,array):
#--------------------
exists = False
while exists == False:
for i in range(len(array)):
if value == array[i]:
exists = True
else:
return exists
#--------------------
starttime = time.time()
for i in range(100000):
for i in range(len(valuelist)):
x = isvalue(valuelist[i],numlist)
endtime = time.time()
print(endtime-starttime,'seconds')
Homework!
Make an algorithm that finds the fastest route that hits every location once starting and ending at Del Norte. Make sure to show your thinking. If you are strugling, try using a huristic approach. Remember, what matters more than having perfectly functioning code is that you tried your hardest.
dataset = {
'DelNorte':{
'Westview':15,
'MtCarmel':20,
'Poway':35,
'RanchoBernardo':50
},
'Westview':{
'DelNorte':15,
'MtCarmel':35,
'Poway':25,
'RanchoBernardo': 45
},
'MtCarmel':{
'Westview':35,
'DelNorte':20,
'Poway':40,
'RanchoBernardo':30
},
'Poway':{
'Westview':25,
'MtCarmel':40,
'DelNorte':35,
'RanchoBernardo':15
},
'RanchoBernardo':{
'Westview':45,
'MtCarmel':30,
'Poway':15,
'DelNorte':50
}
}
def getdistance(order):
miles = 0
x = 0
y = 1
for i in range(3):
current = x
destination = y
dist = dataset[order[current]][order[destination]]
miles = miles + dist
x += 1
y += 1
return miles
from itertools import permutations
min = 5000
for combo in list(permutations(['Westview', 'Poway', 'RanchoBernardo', 'MtCarmel'])):
dist1 = dataset['DelNorte'][combo[0]]
dist2 = dataset[combo[3]]['DelNorte']
finaldist = getdistance(combo) + dist1 + dist2
if finaldist < min:
min = finaldist
minpath = combo
print('Shortest Distance = ', min, ' miles')
print('Del Norte')
for i in minpath:
print(i)
print('Del Norte')